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ClO2− Lewis Structure

Chlorite ion · A bleaching agent used for wood pulp and for treating drinking water.

Lewis structure of ClO2- (Chlorite ion)Each of the two O atoms carries a 1− formal charge and the Cl a 1+; add them up and you get 1−, the charge on the ion. The charge belongs to the ion as a whole, which is what the brackets around the drawing mean.ClOO+--−

The ClO2- Lewis structure has 20 valence electrons - the 1− charge adds one, drawn as two Cl–O bonds, with eight lone pairs in total, all inside square brackets. The central Cl is sp3 hybridized, which makes it a bent ion with a bond angle of 104.5 degrees. Each of the two O atoms carries a 1− formal charge and the Cl a 1+; add them up and you get 1−, the charge on the ion. The charge belongs to the ion as a whole, which is what the brackets around the drawing mean.

The brackets are not decoration. An ion's charge belongs to the whole species, not to one atom, so the structure is drawn inside square brackets with the 1− outside. The small circled numbers inside are formal charges, which are a bookkeeping device for choosing between structures - a different thing entirely. They add up to 1−.

ClO2− molecular geometry

ClO2- molecular geometry: bentClOO

Bent, from 4 electron domains on the central Cl: 2 bonded atoms and 2 lone pairs (AX2E2). The electron geometry is tetrahedral; the shape is what is left when the lone pairs are not counted as atoms. Wedges point toward you, hashed wedges away. Every shape in the VSEPR chart →

Calculated properties

Calculated properties of ClO2-
Total valence electrons 20
Bonding electrons 4 (2 shared pairs)
Nonbonding electrons 16 (8 lone pairs)
Lone pairs on Cl 2
Electron domains (steric number) 4
VSEPR notation AX2E2
Electron geometry tetrahedral
Molecular geometry bent
Bond angle ≈104.5°
Hybridization sp3
Charge 1−
Charge distribution localised
Formal charges Cl: +1, O: -1, O: -1
Resonance structures none
Molar mass 67.448 g/mol

Cl Chlorine 7 valence e− O Oxygen 2 atoms, 6 valence e− each

How to draw the ClO2− Lewis structure

Step through it. The bar shows how much of the 20-electron budget is spent at each stage - it never grows, which is the whole constraint.

  1. ClO2- Lewis structure, stage 1: SkeletonClOO−

    4 of 20 placed

    Skeleton. Join every connected pair with one bond. 2 bonds spends 4 electrons.

  2. ClO2- Lewis structure, stage 2: Outer octetsClOO−

    16 of 20 placed

    Outer octets. Spend electrons as lone pairs on the outer atoms until each has eight. 4 are still unplaced.

  3. ClO2- Lewis structure, stage 3: CentreClOO−

    20 of 20 placed

    Centre. Everything still unplaced goes on Cl, which now has 8 electrons around it.

The reasoning at each step

  1. Count the valence electrons

    Add up the outer-shell electrons every atom brings, then account for the charge. A 1- ion has gained one electron, so it is added to the budget. Skip this and every count that follows will be wrong.

    7 (Cl) + 2 x 6 (O) + 1 (1- charge) = 20 valence electrons
  2. Choose the central atom

    Cl is the least electronegative atom here, so it takes the centre. Hydrogen is never central: it can only form one bond.

  3. Join everything with single bonds first

    Every connection starts as one shared pair. Draw them all before worrying about double bonds - the arithmetic in the next step is what tells you where the double bonds have to go.

    2 bonds x 2 = 4 electrons used, 16 left
  4. Work out how far short you are

    Add up what every atom still needs to fill its shell - eight electrons for most atoms, two for hydrogen - minus what its single bonds already give it. Compare that with the electrons you have left. The difference decides everything that follows.

    needs 16, has 16, exactly enough
  5. Fill in the lone pairs

    Every electron not in a bond sits as a lone pair on an atom. Each atom takes exactly what it needs to finish its shell - there is no choice left at this point.

    Cl: 2, O1: 3, O2: 3 (16 electrons)
  6. Check the central atom

    Cl ends up with a full octet. Every electron in the budget is now placed.

    Cl: 4 bonding + 4 nonbonding = 8
  7. Check the formal charges

    Formal charge is valence electrons, minus lone-pair electrons, minus the number of bonds. They are not real charges, and they are not the ion's charge either - but they must add up to it. Adding these up gives 1-, which is the check that the structure is complete.

    Cl: 7 - 4 - 2 = +1 ; O1: 6 - 6 - 1 = -1 ; O2: 6 - 6 - 1 = -1
  8. Work out the shape

    Count the electron domains on Cl: 2 bonded groups plus 2 lone pairs. A double or triple bond still counts as one domain, because it points in one direction. That gives tetrahedral electron geometry; ignore the lone pairs and the atoms themselves sit in a bent arrangement. Two lone pairs repel more strongly than bonding pairs, closing the angle well below 109.5 degrees.

    steric number 4 -> sp3 -> bent, bond angle 104.5
  9. Decide whether it is polar

    The bond dipoles and lone pairs are arranged symmetrically, so the vectors cancel and the molecule has no net dipole.

    dipoles cancel -> nonpolar

The expanded-octet version

Courses disagree about ClO2-. The structure at the top of this page obeys the octet rule and leaves formal charges behind. The one below puts more than eight electrons on the central atom and brings every formal charge to zero. Check which convention your course uses.

ClO2- drawn with an expanded octetClOO-−
Every formal charge is zero here, but the central atom holds more than eight electrons.

Where the 1− charge sits

Each of the two O atoms carries a 1− formal charge and the Cl a 1+; add them up and you get 1−, the charge on the ion. The charge belongs to the ion as a whole, which is what the brackets around the drawing mean.

People also ask whether ClO2− is polar. Strictly it is neither: polar and nonpolar sort neutral molecules by whether their bond dipoles cancel. A 1− ion is pulled towards any nearby charge whatever its shape, which is why its salts dissolve in water regardless of geometry. The table below is still worth reading - it shows how unevenly each bond holds its electrons, which is what decides whether the charge ends up spread or concentrated.

BondElectronegativity differenceCharacter
Cl–O 0.28 nonpolar covalent
Why this ion gets set as a problem: Two lone pairs on chlorine bend this one much further than its three-oxygen neighbour.

Common questions

How many valence electrons does ClO2- have?

ClO2- has 20 valence electrons. The atoms bring 19 between them, and the 1− charge adds one. 4 of them are in bonds and 16 sit in lone pairs.

Why does ClO2- have a 1− charge?

Each of the two O atoms carries a 1− formal charge and the Cl a 1+; add them up and you get 1−, the charge on the ion. The charge belongs to the ion as a whole, which is what the brackets around the drawing mean. The brackets around the drawing are part of the answer: they say the charge belongs to the whole ion rather than to whichever atom happens to be nearest.

What is the molecular geometry of ClO2-?

ClO2- is a bent ion. The central Cl has 2 bonded groups and two lone pairs, a steric number of 4, which gives tetrahedral electron geometry and a bent ion.

What is the bond angle in ClO2-?

The bond angle in ClO2- is 104.5 degrees. Two lone pairs repel more strongly than bonding pairs, closing the angle well below 109.5 degrees.

What is the hybridization of ClO2-?

The central Cl in ClO2- is sp3 hybridized. Steric number 4 means 4 orbitals have to be mixed, which is exactly what sp3 gives you.

Is ClO2- polar or nonpolar?

Neither, strictly. Polar and nonpolar describe neutral molecules, by asking whether their bond dipoles cancel out. ClO2- carries a net 1− charge, so it is pulled towards any nearby charge whatever its shape - which is why ionic compounds dissolve in water regardless of geometry. The question the shape does answer is whether the charge is spread evenly: it is, because the bent arrangement puts every identical bond at the same angle to the others.

Does ClO2- obey the octet rule?

It can be drawn either way, and different courses teach different conventions. The octet structure keeps eight electrons on every atom but leaves formal charges behind. The expanded-octet structure puts more than eight electrons on the central atom and brings every formal charge to zero. Both are shown on this page.

How this page was produced. The formula was parsed, the connectivity resolved (central atom), and every bond-order arrangement enumerated and scored on octet satisfaction, formal charge and where that charge sits. The structure above is the winner. Bond angles, hybridization and the polarity verdict are read off the resulting geometry, not looked up.