chemcheat

OF2 Lewis Structure

Oxygen difluoride · A toxic, strongly oxidising gas, and a rare compound in which oxygen has a positive oxidation state.

Lewis structure of OF2 (Oxygen difluoride)The O-F bonds are polar, and the lone pairs on the central atom bend the molecule out of shape, so the dipoles do not cancel.OFF

The OF2 Lewis structure has 20 valence electrons, drawn as two O–F bonds, with eight lone pairs in total. The central O is sp3 hybridized, which makes it a bent molecule with a bond angle of 104.5 degrees. OF2 is polar: the O-F bonds are polar, and the lone pairs on the central atom bend the molecule out of shape, so the dipoles do not cancel.

OF2 molecular geometry

OF2 molecular geometry: bentOFF

Bent, from 4 electron domains on the central O: 2 bonded atoms and 2 lone pairs (AX2E2). The electron geometry is tetrahedral; the shape is what is left when the lone pairs are not counted as atoms. Wedges point toward you, hashed wedges away. Every shape in the VSEPR chart →

Calculated properties

Calculated properties of OF2
Total valence electrons 20
Bonding electrons 4 (2 shared pairs)
Nonbonding electrons 16 (8 lone pairs)
Lone pairs on O 2
Electron domains (steric number) 4
VSEPR notation AX2E2
Electron geometry tetrahedral
Molecular geometry bent
Bond angle ≈104.5°
Hybridization sp3
Polarity polar
Formal charges all zero
Resonance structures none
Molar mass 53.995 g/mol

O Oxygen 6 valence e− F Fluorine 2 atoms, 7 valence e− each

How to draw the OF2 Lewis structure

Step through it. The bar shows how much of the 20-electron budget is spent at each stage - it never grows, which is the whole constraint.

  1. OF2 Lewis structure, stage 1: SkeletonOFF

    4 of 20 placed

    Skeleton. Join every connected pair with one bond. 2 bonds spends 4 electrons.

  2. OF2 Lewis structure, stage 2: Outer octetsOFF

    16 of 20 placed

    Outer octets. Spend electrons as lone pairs on the outer atoms until each has eight. 4 are still unplaced.

  3. OF2 Lewis structure, stage 3: CentreOFF

    20 of 20 placed

    Centre. Everything still unplaced goes on O, which now has 8 electrons around it.

The reasoning at each step

  1. Count the valence electrons

    Add up the outer-shell electrons every atom brings. That total is the budget for the whole structure - every line and every dot has to come out of it, and nothing may be added.

    6 (O) + 2 x 7 (F) = 20 valence electrons
  2. Choose the central atom

    O is the least electronegative atom here, so it takes the centre. Hydrogen is never central: it can only form one bond.

  3. Join everything with single bonds first

    Every connection starts as one shared pair. Draw them all before worrying about double bonds - the arithmetic in the next step is what tells you where the double bonds have to go.

    2 bonds x 2 = 4 electrons used, 16 left
  4. Work out how far short you are

    Add up what every atom still needs to fill its shell - eight electrons for most atoms, two for hydrogen - minus what its single bonds already give it. Compare that with the electrons you have left. The difference decides everything that follows.

    needs 16, has 16, exactly enough
  5. Fill in the lone pairs

    Every electron not in a bond sits as a lone pair on an atom. Each atom takes exactly what it needs to finish its shell - there is no choice left at this point.

    O: 2, F1: 3, F2: 3 (16 electrons)
  6. Check the central atom

    O ends up with a full octet. Every electron in the budget is now placed.

    O: 4 bonding + 4 nonbonding = 8
  7. Check the formal charges

    Formal charge is valence electrons, minus lone-pair electrons, minus the number of bonds. Every atom here comes out at zero, which is the sign of a good structure.

    all formal charges = 0
  8. Work out the shape

    Count the electron domains on O: 2 bonded groups plus 2 lone pairs. A double or triple bond still counts as one domain, because it points in one direction. That gives tetrahedral electron geometry; ignore the lone pairs and the atoms themselves sit in a bent arrangement. Two lone pairs repel more strongly than bonding pairs, closing the angle well below 109.5 degrees.

    steric number 4 -> sp3 -> bent, bond angle 104.5
  9. Decide whether it is polar

    The O-F bonds are polar, and the lone pairs on the central atom bend the molecule out of shape, so the dipoles do not cancel.

    dipoles do not cancel -> polar

Is OF2 polar or nonpolar?

OF2 is polar. The O-F bonds are polar, and the lone pairs on the central atom bend the molecule out of shape, so the dipoles do not cancel.

BondElectronegativity differenceCharacter
O–F 0.54 polar covalent
Why this molecule gets set as a problem: The same bent shape as water, with fluorine where the hydrogens were.

Common questions

How many valence electrons does OF2 have?

OF2 has 20 valence electrons. 4 of them are in bonds and 16 sit in lone pairs.

What is the molecular geometry of OF2?

OF2 is a bent molecule. The central O has 2 bonded groups and two lone pairs, a steric number of 4, which gives tetrahedral electron geometry and a bent molecule.

What is the bond angle in OF2?

The bond angle in OF2 is 104.5 degrees. Two lone pairs repel more strongly than bonding pairs, closing the angle well below 109.5 degrees.

What is the hybridization of OF2?

The central O in OF2 is sp3 hybridized. Steric number 4 means 4 orbitals have to be mixed, which is exactly what sp3 gives you.

Is OF2 polar or nonpolar?

OF2 is polar. The O-F bonds are polar, and the lone pairs on the central atom bend the molecule out of shape, so the dipoles do not cancel.

How this page was produced. The formula was parsed, the connectivity resolved (central atom), and every bond-order arrangement enumerated and scored on octet satisfaction, formal charge and where that charge sits. The structure above is the winner. Bond angles, hybridization and the polarity verdict are read off the resulting geometry, not looked up.